linux - Bash, what is the missing argument for variable declaration? -

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• command not found error in bash variable assignment 4 answers

i wrote couple of bash commands in text document.

the first line tries assign bash-command-output-string variable test.

the second line echo whatever in variable test.

for reason error saying "test: missing argument after..."

echo echo echo ////////////////////////////////////////////////////////////// echo echo testing if can return head branch ref #ref = cat ~/desktop/hookerrepo/.git/head | awk '{ print $2 }' test = "$(cat ~/desktop/hookerrepo/.git/head | awk '{ print $2 }')" echo $test #for c in $(test); echo $c; done echo echo ////////////////////////////////////////////////////////////// 

what missing?

an assignment statement cannot include spaces before or after =. following have distinct meanings:

1. a=b: assigns string "b" variable a.
2. a = b: runs command a arguments = , b
3. a= b: runs command b in environment variable a has empty string value.
4. a =b: runs command a argument =b.