mysql - Find all employee who have worked on at least two projects -


table: projectressources

idproject  idemployee  numhours   priceperhr 1          1876       500        65 1          4354       2000       31 2          2231       250        55 3          2231       500        65 3          1212       3000       35 3          1876       2000       35

i come following research syntax can't figure how filter indicate 2231 , 1876:

select idemployee, count (*) ‘number of projects’ projectressources group idemployee;

you're headed in right direction. missing piece having clause allows filter aggregate expression, such count(*):

select   idemployee, count (*) ‘number of projects’      projectressources group idemployee having   count(*) > 1 -- here!

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