c - Hexadecimal being truncated -


why when attempt print value of argv (which according eclipse particular run of program below 0x7fffffffd958) ffffd958 instead of 7fffffffd958? 

int main (int argc, char *argv[]) {     printf("%x \n", argv);     return 0; }

long story short: invoking undefined behavior because of wrong format specifier. use instead:

printf("%p \n", (void *) argv);

the reason why different value %x treats argv 32-bit unsigned integer on platform. probably use %lx (or possibly %llx), still bad , incorrect practice, since argv of pointer type.


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