c - Why is scanf of a string saved to str while for the int it is being sent to the pointer of i? -

i have code:

char str [80]; int i; printf ("enter family name: "); scanf ("%79s",str);   printf ("enter age: "); scanf ("%d",&i);

why scanf() of string saved str while int being sent pointer of i?

scanf needs passed address of variable in order modify it.

when passing array (a char array, in case) function, array decays pointer first element.

so passing str %s specifier functionally same passing in &str[0].

this works char * points dynamically allocated memory:

char *str = malloc(80); scanf ("%79s",str);

Two