c++ - Alternate highest counting in array -


i have array sorted contains zeroes in between 

a[10]={0,0,3,5,0,6,7,0,9,0}

i want neglect zeroes , find sum of alternate elsments i.e. 3+6+9 , 5+7 seperately. here m trying do

while(i<10) {      if(a[i]!=0)      {          s1=s1+a[i];          i++;      }      if(a[i]!=0)      {          s2=s2+a[i]          i++;      }      i++; }

any alternate this??

use boolean keep track of sum add element to:

bool alt = true; int sum1 = 0; int sum2 = 0; for(int = 0; i<10; ++i) {     if(a[i])     {         if(alt)         {             sum1 += a[i];         }         else         {             sum2 += a[i];         }         alt = !alt;     } }

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