Detect if input is a alphabet in python 3.5? -


hello part of code i'm working on. wanted know if there way detect if input typed alphabet , give response. need subtracted time converted int if other int type if gives me error.

def continue():     time = int(input("what time it?: "))     if time > 12:         print ("i'm sorry, hour, don't need anymore that.")         continue()     else:         print ("it's %d" % time + "?!")         time = time - 1         print ("i'm late!\ni'm sorry have go!\ni'm sure leg fine walk off!")         print ("i suppose there @ %d" % time, "i'm hour late!")

this want:

def continue():     try:         time = int(input("what time it?: "))     except valueerror:         print('invalid input.')         print('please enter number between 1 , 12.')         continue()     if time > 12:         print("i'm sorry, hour, don't need anymore that.")         continue()     else:         print("it's %d" % time + "?!")         time = time - 1         print ("i'm late!\ni'm sorry have go!\ni'm sure leg fine walk off!")         print ("i suppose there @ %d" % time, "i'm hour late!")

you can use try-except statement. python raise valueerror if conversion integer fails. in case, catch exception except, tell user input wrong, , call function again.


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