Compare a bidimensional array to 0 (c++) -

i made loop do.while, trying make change turns of game. now, want stop when of both array comes 0, , show winner. battleship game.

do{ for(int k;toc=1;k++){     objec1();       if(toc!=1)       break;         }       for(int k;toc2=1;k++){         objec2();            if(toc2!=1){              break;            }             }          if(jug1[i][j]==0){ //here loop must stop     correct1=true;  cout<<"\n\tel player 2 winner\n";  } if(jug2[i][j]==0){     correct1=true;  cout<<"\n\tplayer 1 winner \n";  }  } while(!correct1);  

in way have code, not stop loop when must. now, want check if when array full of 0, stop loop, change flag , show winner. original code more extense. consider correctly initialized.

firstly, think you'll have easier time problem if fix formatting, break things functions, , use better variable names. pretty hard read , understand.

secondly, operation talking pretty expensive. if can avoid doing check way, that'd better. example, maintain count of non-zero entries, , instead use check condition. or, if have information battleships in play, check when none of them left.

anyway, here function find out "when [two-dimensional] array full of 0". can call function.

/**  * array 2-d array used battleship game  * outer array size  * j inner array size  */ bool isallzeros(int **array, int i, int j) {     (int m = 0; m < i; m++) {         (int n = 0; n < j; n++) {             if (0 != array[i][j]) {                 return false;             }         }        }         return true; }