python - searching for doubles with regular expressions -


this question has answer here:

is there regular expression match floating point numbers not if part of construct 15.01.2016?

re.match(rex, s) should successful if s be

1.0a 1.b .1

and not successful s like

1.0.0 1.0.1 20.20.20.30 12345.657.345

edit: crucial part combination of constrains: "[0-9]*\.[0-9]*" , not part of "[0-9]+\.[0-9]+(\.[0-9]+)+"

you can use regex based on arounds in python:

(?<![\d.])(?:\d*\.\d+|\d+\.\d*)(?![\d.])

regex demo

  • (?![\d.]) lookahead assertion fail match if next char dot or digit
  • (?<![\d.]) lookbehind assertion fail match if previous char dot or digit

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