C program to print trapezoid pattern of numbers,stars & hypens -

i asked in test today.

i had print following pattern:-

for example if user input n=4 output should of pattern-
1*2*3*4*17*18*19*20
--5*6*7*14*15*16
----8*9*12*13
------10*11

again if n=5 code should print
1*2*3*4*5*26*27*28*29*30
--6*7*8*9*22*23*24*25
----10*11*12*19*20*21
------13*14*17*18
--------15*16

i manage print pattern partially...help..
progress far...

#include <stdio.h> void pattern(int); int main() {     int n;     scanf("%d",&n);     pattern(n);     return 0; } void pattern(int n) {     int i,j,k=1,l=2,h;     for(i=n;i>0;i--)     {         if(i<n)             {                 for(h=1;h<=l;h++)                     printf("-");                     l=l+2;             }         for(j=1;j<=i;j++)         {             printf("%d",k);             k++;             if(j!=i)                 printf("*");         }         printf("\n");       } } 

this prints n=4:-

4   1*2*3*4   --5*6*7   ----8*9   ------10 

there go :

#include<stdio.h> void pattern(int); int main() {   int n;   scanf("%d",&n);   pattern(n);   return 0; } void pattern(int n) {   int i,j,k=1,l=2,h;   int rest=n*(n+1)+1,rn=0;    for(i=n;i>0;i--)     {       if(i<n)         {           for(h=1;h<=l;h++)             printf("-");           l=l+2;         }       for(j=1;j<=i;j++)         {           printf("%d",k);           k++;                      printf("*");         }        rest=rest-i;       rn=rest;        for(int p=1;p<=i;p++)         {                 printf("%d",rn);           rn++;           if(p!=i)             printf("*");          }       printf("\n");       } } 

i see did job in printing hypens , half numbers. left other half should decremented each line. highest number need print n*(n+1). compute number (in variable rest) , need decrement each line i(half of number of elements on row).