oracle11g - Interval of consecutive numbers with Oracle SQL and JOINS -


i'm trying display intervals of consecutive elevations in iceland, per row, in form this:

elevation             0        27          29       33          35          37       40          42       46          48          51       63

for now, managed track gaps, have in mind like:

if (count of values in columnb until columnc='gap') equals value of columnb columnc='gap' have consecutive interval between value of columna , column b

can give me tips ?

current code

with x (     select distinct elevation     cities     iso = 'is' , iso not null ),y (     select a.elevation "a",b.elevation "b",c.elevation "c" x    join x b on b.elevation > a.elevation   left join x c on c.elevation > b.elevation , c.elevation < b.elevation + 2 )select y.a,y.b,y.c,case when y.c null 'gap' else ' ' end  gapz y order 1,2

output

  b   c   gap ------------------ 0   1   2     0   2   3     0   3   4     ... ... ...   0   25  26    0   26  27    0   27      gap 0   29  30    0   30  31    0   31  32    0   32  33    0   33      gap 0   35      gap 0   37  38    0   38  39    0   39  40    0   40      gap 0   42  43    0   43  44    0   44  45    0   45  46    0   46      gap 0   48      gap 0   51  52    0   52  53    ... ... ... 0   61  62    0   62  63    0   63      gap 0   65  66    0   66  67    0   67  68    0   68  69    0   69      gap 0   71  72    ... ... ...

you're halfway there! need flag either end of gap, select rows.

select x,              case lead(x,x) over(order x)                  when x+1 null                  else x              end endpoint,              case lag(x,x) over(order x)                   when x-1 null                   else x               end startpoint   table

this show whether row start or endpoint. let's call q1. select need that.

select q1.startpoint,             (select min(endpoint)                q1 endp              endp.endpoint >= q1.x) endpoint  q1  q1.startpoint not null

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