Parsing XML data in C# and show into ListBox -


i trying parse xml file in c# using visual studio , show data in listbox, don't know how parse when i'm dealing nested xml file.

this code xml file:

<?xml version="1.0" encoding="utf-8" ?> <!doctype root [   <!element root (persons*)>   <!element persons (name)>   <!element ismale (#pcdata)>   <!element age (#pcdata)>   <!element name (#pcdata)>   <!element likedperson (name)>  ]> <root>   <persons name ="bob">     <ismale>true</ismale>     <age>30</age>     <likedperson name ="iulia">       <ismale>false</ismale>       <age>32</age>     </likedperson>   </persons> </root>

the code i've written in c# return me name, gender , age every person, don't know how write show me person_liked:

private void loadpersons()     {         xmldocument doc = new xmldocument();         doc.load("baza_de_cunostinte.xml");          foreach (xmlnode node in doc.documentelement)          {             string name = node.attributes[0].value;             int age = int.parse(node["age"].innertext);             bool ismale = bool.parse(node["ismale"].innertext);  //          persons likedperson.name = persons.node.attributes[0].value ?   //          .....              listbox.items.add(new persons(name, age, ismale, likedperson));         }     }      private void listbox_selectedindexchanged(object sender, eventargs e)     {         if (listbox.selectedindex != -1)         {             propertygrid1.selectedobject = listbox.selecteditem;         }     }

this definition of persons.cs :

class persons {     public string name { get; private set; }     public int age { get; private set; }     public bool ismale { get; private set; }     public persons likedperson { get; private set; }      public persons(string name, int age, bool ismale, persons likedperson)     {         name = name;         age = age;         ismale = ismale;         likedperson = likedperson;     } } 

xmlserializer myserializer = new xmlserializer(typeof(persons)); // create filestream or textreader read xml data. filestream myfilestream = new filestream("xmldatafile.xml", filemode.open);  var person = (persons)  myserializer.deserialize(myfilestream);

you need add constructor without parameter persons class.


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