c++ convert 2 bytes of hex into integer -


i developing little embed app sends , responds chunk of data {80,09,1d,00,00} (all values in hexadecimal format) , being stored in vector<int>. have been looking method transforms bytes int type integer (c++). have been looking around cannot right answer, have code test results:

#include <iostream> #include<stdio.h> #include <vector> using namespace std;  int main() {      int x = 0x2008;//expected number result process      vector<int> acmdresult;     acmdresult.push_back(0x20);     acmdresult.push_back(0x08);     int aresult=0;     aresult= (acmdresult.at(0)&0xff) | ( (acmdresult.at(1)>>8)&0xff) ;     cout<<std::hex<<"conversion result: "<<aresult<<endl;     /* 2 bytes of hex = 4 characters, plus null terminator */     x=0x0014;//expected number result process     aresult=0;     acmdresult.clear();     acmdresult.push_back(0x00);     acmdresult.push_back(0x14);     aresult= (acmdresult.at(0)&0xff) | ( (acmdresult.at(1)>>8)&0xff) ;     cout<<std::hex<<"conversion result: "<<aresult<<endl;        return 0; }

the result first output is: 0 , in second is: 20 these not correct values! in advance

finally :

#include <iostream> #include<stdio.h> #include <vector> using namespace std;  int main() {      int x = 0x2008;//expected number result process      vector<int> acmdresult;     acmdresult.push_back(0x20);     acmdresult.push_back(0x08);     int aresult=0;     aresult= ((acmdresult.at(0)&0xff)<<8) | ( (acmdresult.at(1))&0xff) ;     cout<<std::hex<<"conversion result: "<<aresult<<endl;     /* 2 bytes of hex = 4 characters, plus null terminator */     x=0x0014;//expected number result process     aresult=0;     acmdresult.clear();     acmdresult.push_back(0x00);     acmdresult.push_back(0x14);     aresult= (acmdresult.at(0)<<8&0xff) | ( (acmdresult.at(1))&0xff) ;     cout<<std::hex<<"conversion result: "<<aresult<<endl;        return 0; }

what tryng , forth convertion array integer , , integer (i think using xor 2 bytes rigth side??)


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