xslt 1.0 - Unable to Successfully Pass Parameters to xsl:call-template -


i have generic template i've designed 2 params title , category.

<?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.1"             xmlns:xsl="http://www.w3.org/1999/xsl/transform"             xmlns:fo="http://www.w3.org/1999/xsl/format">      <xsl:param name="category" />     <xsl:param name="title" />     <xsl:template name="test-group">         <fo:block>             <xsl:value=of select="$title" />         </fo:block>         <fo:block>             <xsl:value-of select="$category" />         </fo:block>     </xsl:template> </xsl:stylesheet>

in parent template have following:

<?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.1" xmlns:xsl="http://www.w3.org/1999/xsl/transform"             xmlns:fo="http://www.w3.org/1999/xsl/format">     <xsl:include href="templates/generic_template.xsl" />     ...     <xsl:call-template name="test-group">         <xsl:with-param name="category" select="'animals'" />         <xsl:with-param name="title" select="'dogs'" />     </xsl:call-template>     ... </xsl:stylesheet>

however, when transform completes title , category blank. i'm using fop 2.0 i'm not sure if known shortcoming.

when defining xsl:template takes parameters, parameter names used within xsl:template should declared using xls:param elements nested within.

<xsl:template name="test-group">   <xsl:param name="category" />   <xsl:param name="title" />   ... </xsl:template>

the parameters being attached xsl:template , not xsl:stylesheet. similar when calling template xsl:call-template, except specifying values instead using xsl:with-param.


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