C two-dimensional array based on user input -

i'm trying assign user input using two-dimensional array takes 5 numbers , squares them. program should calculate , store squared values each user in array.

i'm getting right output current code can't figure out how assign input array, without getting errors in output.

#include <stdio.h>  int main(void) {     int disp[2][5];      int x, y;     printf("please enter 5 integer values:\n");      for(x=0; x<=2; x++) {          (y=0; y<=5; y++) {             scanf("%d", &x);             printf("[ %d ][ %d ]\n", x, x*x);         }     }      return 0; } 

the following code scans 5 numbers, , stores squares in array (which never used again):

#include <stdio.h>  #define num_items 5 // store number of items in 1 place  int main() {     int disp[2][num_items];     int i;      printf("please enter %d integer values:\n", num_items);      (i = 0; < num_items; ++i) {          if ( scanf("%d", &disp[0][i]) == 1 ) {             // check return value of scanf()              disp[1][i] = disp[0][i] * disp[0][i]; // store squares in array             printf("[ %d ][ %d ]\n", disp[0][i], disp[1][i]);         }         else {             printf("error in scanf()\n");             break;         }     }      return 0; } 

---

i'm trying assign user input using two-dimensional array takes 5 numbers , squares them. program should calculate , store squared values each user in array.

some issues code:

for(x=0; x<=2; x++) { // overflows array (0, 1 , 2)                       // should x < 2     (y=0; y<=5; y++){ // idem -> y < 5         scanf("%d", &x);  // scanf() called 10 times                   // x used loop counter!         printf("[ %d ][ %d ]\n", x, x*x);              // squares never stored in array     } }