In Java catch block, how do you know which method/line throws the exception? -

in try block, want execute 2 functions. if first 1 failed don't execute second. want print out function failed.

see following code.

try {   = func1();   b = func2();  //won't execute if failed } catch (exception e) {   //todo: print or b failed? } 

does language support scenario naturally?

if not, following practice? (i cannot think of wrong it. concerns me don't remember seeing 1 using return in catch.)

try {   = func1(); } catch {   //print: failed   return; //if failed skip execution of b }  try {   b = func2(); } catch {   //print: b failed } 

edit: summary of comments:

1. throw different exception 2 methods.

   • in case methods written others , have no control.

2. e.printstacktrace() print line number , function

   • i want more printing. more like, if failed, execute following code.

what want string methodname = e.getstacktrace()[0].getmethodname());

but hardly practice. standard way log exception using appropriate method in logging framework or (if writing console app, case java) print error or standard output or optionally other printstream, example using printstacktrace(printstream).

but in cases want propagate exception upper layers , handle (or decide not handle it) appropriate high level code. catching exceptions leads nasty bugs. returning catch black bad idea in 99% of cases because exception signalizes abnormal termination of method while returning value not.