javascript - Remove empty properties of knockout viewModel -
this turned out harder thought. have viewmodel use filtering in grids. here is:
var gridfiltersviewmodel = function () { var self = this; self.search = ko.observable(); self.sortcolumn = ko.observable(); self.sortdirectionisascending = ko.observable(true); self.page = ko.observable(1); self.pagesize = ko.observable(10); self.pagecount = ko.observable(); self.itemcount = ko.observable(); }; the issue i'm faced when send instance of viewmodel towards action method error:
the value 'null' not valid property
this happens because server-side viewmodel properties not accept null , undefined properties of client-side viewmodel when set them nullable. way have server-side viewmodel accept empty properties not send them @ all. attempt @ that:
var gridfiltersviewmodel = function () { // properties before self.removeemptyproperties = function () { (var property in self) { if (self[property] === null || self[property] === undefined) { delete self[property]; } } }; }; suffice say, not work. end undefined object when method finishes. i've tried converting knockout viewmodel javascript object (using ko.tojs()) before running method same result.
what doing wrong here , how do right?
i construct new json object , return rather try exotic removing properties... this:
var gridfiltersviewmodel = function () { var self = this; self.prop1 = ko.observable(null); self.prop2 = ko.observable('test'); self.prop3 = ko.observable(undefined); self.definedproperties = ko.computed(function () { var json = {}; json.props = ""; (var property in self) { if (self[property]() !== null && self[property]() !== undefined) { json[property] = self[property](); if (json.props !== "") { json.props += ", "; } json.props += property; } } return json; }); }; full example here: https://jsfiddle.net/brettwgreen/ehy7cmud/2/
Comments
Post a Comment