c# - Can I use the keyword "in" to separate parameters in a method declaration somehow? -

i create method uses keyword in instead of comma separate parameters in method declaration; similar foreach(a in b) method.

example

class structure

public class length {     public double inches;     public double feet;     public double yards;      public enum unit { inch, foot, yard }      dictionary<unit, double> inchfactor = new dictionary<unit, double>()     {         { unit.inch, 1 },         { unit.foot, 12 },         { unit.yard, 36 }     };      public length(double value, unit unit)     {         this.inches = value * inchfactor[unit];         this.feet = this.inches / inchfactor[unit.foot];         this.yards = this.inches / inchfactor[unit.yard];     } } 

method definition in class

// i'd know how use "in"  ↓ public list<length> multiplesof(length divisor in length dividend) {     double inchenumeration = divisor.inches;     list<length> multiples = new list<length>();      while (inchenumeration <= dividend.inches)     {         multiples.add(new length(inchenumeration, length.unit.inch));         inchenumeration += divisor.inches;     }      return multiples; } 

ideal implementation

private void drawruler() {     length eighthinch = new length(0.125, length.unit.inch);     length onefoot = new length(1, length.unit.foot);      // awesome.     list<length> tickgroup = length.multiplesof(eighthinch in onefoot);      double inchpixels = 10;     foreach (length tick in tickgroup)     {         // draw ruler.     } } 

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i've looked creating new keywords, looks c# not support defining keywords.

while can't redefine existing keyword, there other way accomplish in different way using fluent interface :

public class length {     // ...      public static ifluentsyntaxprovider multiplesof(length divisor)     {         return new fluentsyntaxprovider(divisor);     }      public interface ifluentsyntaxprovider     {         list<length> in(length dividend);     }     private class fluentsyntaxprovider : ifluentsyntaxprovider     {         private length divisor;          public fluentsyntaxprovider(length divisor)         {             this.divisor = divisor;         }          public list<length> in(length dividend)         {             double inchenumeration = divisor.inches;             list<length> multiples = new list<length>();              while (inchenumeration <= dividend.inches)             {                 multiples.add(new length(inchenumeration, length.unit.inch));                 inchenumeration += divisor.inches;             }              return multiples;         }     } } 

example of usage :

// awesome. list<length> tickgroup = length.multiplesof(eighthinch).in(onefoot);